How to Reduce 48 Volts DC to 24 Volts DC With Resistors

Written by pallav pathak
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How to Reduce 48 Volts DC to 24 Volts DC With Resistors
Resistors come with various values of resistances, usually determined by the colours on them. (widerstand, resistor image by Sascha Zlatkov from

If you are presented with a battery of voltage higher than what you require, you can easily gain access to a lower value by employing resistors in the circuit. This method is a direct implementation of the Voltage Divider Rule which states that voltage gets divided among the resistors in proportion to their resistance values. Consequently, connecting the load in parallel to the second resistor allows you to gain access to the same voltage drop that the resistor has access to.

Skill level:

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Things you need

  • Two 1000-ohm resistors
  • Jumper wire of desired length

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  1. 1

    Buy two 1000 ohm resistors online or from your local electronics store, along with a desired length of jumper wire to connect all the components. The resistances of the two resistors purchased should be equal because you will be dividing the battery voltage exactly in half.

  2. 2

    Connect the resistors end to end to the positive terminal of the battery using some jumper wire. Connect them by twisting the jumper wire ends around the component ends; this configuration is called a series configuration. Because both resistors are identical, voltage is divided equally between them, as per the Voltage Divider Rule. This means that both resistors have a voltage drop of 24 volts across them.

  3. 3

    Connect your load in parallel with either one of the resistors. This is called a parallel configuration, and it is achieved by connecting the left ends of both the load and the resistor and then doing the same with the right ends. Again, the connection can be done by using jumper wire and twisting it around the component terminals. Once you are done, the two components will appear to be parallel to each other. You now have access to the reduced voltage.

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